If you drink 2 liters of water with a temperature of 20 degrees Celsius and your body exits the water at a temperature of 36 degrees Celsius, your body will lose a certain amount of heat energy as the water passes through it and absorbs some of your body’s heat. The amount of heat energy your body loses can be calculated using the same formula as before:
Q = mL * c * deltaT
Q is the energy lost by your body, in calories
m is the mass of the water, in kilograms
L is the specific heat capacity of water, which is 4.184 Joules/gram-degree Celsius
c is the specific heat capacity of water, which is 1 calorie/gram-degree Celsius
deltaT is the change in temperature of the water, in degrees Celsius
To calculate the amount of energy your body loses, you would do the following:
Convert the volume of water from liters to grams: 2 liters = 2000 grams
Calculate the change in temperature: deltaT = 36 degrees Celsius – 20 degrees Celsius = 16 degrees Celsius
Plug the values into the formula: Q = (2000 grams) * (4.184 Joules/gram-degree Celsius) * (1 calorie/gram-degree Celsius) * (16 degrees Celsius) = 167360 calories
Therefore, your body would lose approximately 167,360 calories as the 2 liters of water pass through it and absorb some of your body’s heat.
It’s worth noting that this is a rough estimate and does not take into account the many other factors that can affect your body’s heat loss, such as your body’s surface area, the ambient temperature, and your clothing.